Q.1. Two numbers are in the ratio 2 : 3. If their L.C.M. is 48.
What is sum of the numbers?
a) 28
b) 40 c) 64 d)
42 e) 32
Ans: b
Explanation:
Let the two numbers be 2x and 3x
respectively.
LCM of 2x and 3x = 6x
Given, 6x = 48
So, x = 8
The required sum = 2x + 3x = 16 + 24
= 40. Ans.
Q.2. What is the greatest number of
four digits which is divisible by 15, 25, 40 and 75 ?
a) 9800 b) 9600
c) 9400 d) 9200 e) 9000
Ans: b
Explanation:
The greatest 4- digit number =
9999
LCM of 15, 25, 40 and 75 = 600
The remainder obtained when 9999 is
divided by 600 = 399
Therefore, the required greatest
number = 9999 – 399 = 9600 Ans.
Q.3. Three numbers are in the ratio of
2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is:
a) 40 b) 30 c) 20
d) 10 e) None of these
Ans: c
Explanation :
Let the numbers be 2x, 3x and 4x
LCM of 2x, 3x and 4x = 12x
=> 12x = 240
=> x = 240⁄12 = 20
H.C.F of 2x, 3x and 4x = x = 20
LCM of 2x, 3x and 4x = 12x
=> 12x = 240
=> x = 240⁄12 = 20
H.C.F of 2x, 3x and 4x = x = 20
Q.4. Find
the minimum number of square tiles required to pave the floor of a room of 2m
50cm long and 1m 50cm broad ?
a)
50 b) 750 c) 45 d) 15
e) None of these
Ans: d
Explanation:
HCF of 250 cm and
150 cm is 50 cm, which is the side of the tile
So, the required number of tiles = (250 × 150) / (50 × 50) = 15
So, the required number of tiles = (250 × 150) / (50 × 50) = 15
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