Q.1. Two numbers are in the ratio 2 : 3. If their L.C.M. is 48.
What is sum of the numbers?
a)       28      
b) 40     c) 64      d)
42      e) 32
Ans: b
Explanation:
Let the two numbers be 2x and 3x
respectively.
LCM of 2x and 3x = 6x
Given, 6x = 48
So, x = 8
The required sum = 2x + 3x = 16 + 24
= 40. Ans.
     Q.2. What is the greatest number of
four digits which is divisible by 15, 25, 40 and 75 ?
             a) 9800     b) 9600    
c) 9400       d) 9200       e) 9000
              Ans: b
             Explanation:
             The greatest 4- digit number =
9999
             LCM of 15, 25, 40 and 75 = 600
            The remainder obtained when 9999 is
divided by 600 = 399
            Therefore, the required greatest
number = 9999 – 399 = 9600 Ans.
     Q.3. Three numbers are in the ratio of
2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is:
           a) 40       b) 30        c) 20   
d) 10      e) None of these
           Ans: c
            Explanation : 
Let the numbers be 2x, 3x and 4x
LCM of 2x, 3x and 4x = 12x
=> 12x = 240
=> x = 240⁄12 = 20
H.C.F of 2x, 3x and 4x = x = 20
LCM of 2x, 3x and 4x = 12x
=> 12x = 240
=> x = 240⁄12 = 20
H.C.F of 2x, 3x and 4x = x = 20
     Q.4.  Find
the minimum number of square tiles required to pave the floor of a room of 2m
50cm   long and 1m 50cm broad ?
a)     
50      b) 750      c) 45       d) 15    
e) None of these 
          Ans: d
          Explanation:
  HCF of 250 cm and
150 cm is 50 cm, which is the side of the tile
So, the required number of tiles = (250 × 150) / (50 × 50) = 15
So, the required number of tiles = (250 × 150) / (50 × 50) = 15
 
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